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Thinker8921
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I know the L/T^2 relationship of a simple pendulum gives a constant- g/(2pi)^2.
Could anyone please show me how it is derived?
Thanks in advance.
Could anyone please show me how it is derived?
Thanks in advance.
Thinker8921 said:I know the L/T^2 relationship of a simple pendulum gives a constant- g/(2pi)^2.
Could anyone please show me how it is derived?
Thanks in advance.
Welcome to PF, by the way.Thinker8921 said:Thankyou for the reply. I think I should have been a little clearer. I am in high school and this depth is a little new so I don't understand the whole explanation.
That's right.-The theta sign with the 2 dots*, I am thinking it is angular acceleration? That way, mLa will be torque of the pendulum bob.
These are parameters for the initial condition. The A0 (I could have said [itex]\theta_0[/itex]) is the maximum value of [itex]\theta[/itex], which occurs when the sin term = 1. The [itex]\phi[/itex] is simply to adjust for the phase - ie. when the amplitude maximum occurs in relation to t. For example if amplitude was maximum at t=0, you would set [itex]\phi = \pi/2[/itex] so that the sin term gave a value of 1 (which is the maximum value for sin).- I get the differential, however not the next step with the A zero sign and phi sign. What do they represent. Is it (Started calculus a week ago).
You have to use Latex. See https://www.physicsforums.com/showthread.php?t=8997" for help on Latex.*How do I insert the actual symbols in this?
The length/time period squared relationship of a simple pendulum is an important concept in physics that describes how the length of a pendulum affects its time period, or the time it takes for one complete swing. This relationship was first discovered by Galileo in the 16th century and is expressed as T^2 = 4π^2(L/g), where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity.
As the length of a pendulum increases, its time period also increases. This means that the longer the pendulum, the longer it takes for one complete swing. This is because the longer pendulum has a larger swing arc and therefore takes a longer time to complete one cycle.
The length/time period squared relationship is significant because it allows us to accurately predict the time period of a pendulum based on its length. This relationship has been used in various fields, such as clock-making and seismology, and has helped scientists better understand the concept of periodic motion.
No, the mass of the pendulum does not affect its time period. As long as the length and amplitude of the pendulum remain constant, the time period will also remain constant regardless of the mass. This is because the force of gravity acts equally on all objects, regardless of their mass.
The length/time period squared relationship can be verified experimentally by conducting a simple pendulum experiment with different lengths and measuring the time period for each length. The results can then be plotted on a graph, with length on the x-axis and time period squared on the y-axis. The graph should show a linear relationship, confirming the validity of the equation T^2 = 4π^2(L/g).