Lens Refraction Problems: Help with Calculating Image Distance and Magnification

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SUMMARY

This discussion focuses on solving lens refraction problems using the lens equation. The first problem involves a converging lens with a focal length of 85 cm and an object distance of 121 cm, requiring calculations for image distance and height. The second problem features a converging lens with a focal length of 59.2 cm and an object distance of 38.2 cm, necessitating image distance and magnification calculations. The third problem addresses a diverging lens with a focal length of -14 cm, where the object must be positioned to achieve a specific image size reduction.

PREREQUISITES
  • Understanding of the lens equation
  • Knowledge of focal lengths and object distances
  • Ability to calculate magnification
  • Familiarity with converging and diverging lenses
NEXT STEPS
  • Study the lens equation in detail
  • Practice problems involving converging and diverging lenses
  • Learn how to derive magnification formulas
  • Explore real-world applications of lens optics
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Students studying optics, physics educators, and anyone interested in understanding lens behavior and image formation.

moonlit
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I'm really not sure how to figure these 3 problems out. Can someone please help me. Thanks.

1) A converging lens has a focal length of 85 cm. A 14-cm-tall object is located 121 cm in front of this lens. (a) What is the image distance? (b) What is the image height? Be sure to include the proper algebraic sign.

2) An object is located 38.2 cm to the left of a converging lens whose focal length is 59.2 cm. (a) Determine the image distance and (b) the magnification.

3) An object is 27 cm in front of a diverging lens that has a focal length of -14 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.1?
 
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I got the last one but the other two I'm still unsure of...
 
If you would like some help, show your work and I'll take a look.
 
Nevermind, I figured it out. Thanks anyway!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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