Lenz's Law Q: Clockwise or Counterclockwise?

AI Thread Summary
The discussion focuses on determining the direction of induced current in a loop of wire as it moves past a straight wire carrying current. At position A, the induced current is clockwise due to the magnetic field created by the wire, which points out of the page, leading to a resistance against the flux change. At position B, despite the loop moving away from the wire and the flux decreasing, the magnetic field direction remains the same, resulting in a clockwise current instead of counterclockwise. The reasoning behind the current direction is clarified by understanding how the magnetic flux changes as the loop crosses the wire. Overall, the key takeaway is that the induced current remains clockwise in both positions due to the consistent direction of the magnetic field from the wire.
lenzlawquestion
Messages
2
Reaction score
0

Homework Statement


A long, straight wire lies on a table and carries a current I. As the drawing shows, a small circular loop of wire is pushed across the top of the table from position 1 to position 2. Determine the direction of the induced current, clockwise or counterclockwise, as the loop moves past position 1 and position 2.

Homework Equations



No equations, but the right hand grip rule is relevant.

The Attempt at a Solution



So I got the first part of the question right. I know that because the wire's current is going right, the right hand grip rule suggests that the magnetic field is pointing out of the screen/page. At position A, the table top has no field and the wire will want to resist the flux change. Therefore, a field will point downwards, opposite the direction of that of the wire, leading to a clockwise current at A.

However, B also has a clockwise current. My reasoning was that if the looped wire is within the field generated by the wire, its magnetic field would also be out of the screen/page, and therefore if it is pushed back to the flux-less table top, the flux would decrease. To oppose this, I thought that the secondary magnetic force would be out of the page, and the loop at B would be counterclockwise. So why is it actually clockwise?
 

Attachments

  • Electromagnetic_Induction_P2a.JPG
    Electromagnetic_Induction_P2a.JPG
    4.7 KB · Views: 685
Physics news on Phys.org
lenzlawquestion said:
To oppose this, I thought that the secondary magnetic force would be out of the page, and the loop at B would be counterclockwise. So why is it actually clockwise?
In the first situation (1) the loop closes up the wire: the flux through the loop increases.
In the second situation the loop moves away from the wire ( the flux in the loop decreases ) but at the same time, the flux from the wire has changed direction:

http://onlinephys.com/magnet6.gif
 
How do you know that the flux from the wire has changed direction? What causes it to be different from that in position A?
 
lenzlawquestion said:
How do you know that the flux from the wire has changed direction? What causes it to be different from that in position A?
Draw a line on the paper in the figure in #2, crossing the center/wire. This line is the surface of the table. Following this line in one direction, the flux will change sign when you cross the wire/center.

It's like crossing a road: Crossing the middle of the road, the traffic will come from the other side.
 
Last edited:
  • Like
Likes lenzlawquestion
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top