How to Evaluate a Limit at Infinity with Exponential Functions

[Ionophore]

Can someone give me a hint on how to evaluate the following limit?

<br /> \stackrel{lim}{T\rightarrow\infty} (Texp(c/T) - T)<br />

I tried multiplying the numerator and denominator by the conjugate (because that sometimes helps) and got:

<br /> (T^2exp(2c/T) - T^2) / (Texp(c/T) + T)<br />

But I'm not sure what I can do from there...

 

[nicktacik]

You can express it as

\lim_{x\rightarrow\infty} \frac{e^{c/x} - 1}{x^{-1}}}

Then apply l'hopital's rule

 

[Curious3141]

Even faster, just observe that c/T -> 0 as T-> inf and use Maclaurin's for e^(c/T) up to the first order term.

 

[Hurkyl]

Here's a typesetting tip:

\lim_{x \to a}

results in

\lim_{x \to a}

Furthermore, if you wanted to create your own custom one, you would do this:

\mathop{\mathrm{Hur}}_{a = 1}^{b = 7}

to get

\mathop{\mathrm{Hur}}_{a = 1}^{b = 7}