- #1

SqueeSpleen

- 141

- 5

Find

http://imageshack.us/a/img35/1637/lineal2.gif [Broken]

http://imageshack.us/a/img210/1370/lineal1.gif [Broken]

C^3 is the canonical base of ℝ^3, C^2 is the canonical base of ℝ^2

I tried:

http://imageshack.us/a/img822/6274/lineal3.gif [Broken]

But I'm not sure if this is right, I made a mistake here or I'm not checking this right.

I think, if this is well done I have to have the same answer when putting the vectors of canonical basis (1,0,0), (0,1,0), (0,0,1), the result in canonical ℝ^2 has to be the same result that I got if I use (1,0,1), (1,1,1), (1,0,0) in ℝ^2 using B'

I hope I was clear enough, I don't speak English very well.

http://imageshack.us/a/img35/1637/lineal2.gif [Broken]

http://imageshack.us/a/img210/1370/lineal1.gif [Broken]

C^3 is the canonical base of ℝ^3, C^2 is the canonical base of ℝ^2

I tried:

http://imageshack.us/a/img822/6274/lineal3.gif [Broken]

But I'm not sure if this is right, I made a mistake here or I'm not checking this right.

I think, if this is well done I have to have the same answer when putting the vectors of canonical basis (1,0,0), (0,1,0), (0,0,1), the result in canonical ℝ^2 has to be the same result that I got if I use (1,0,1), (1,1,1), (1,0,0) in ℝ^2 using B'

I hope I was clear enough, I don't speak English very well.

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