Linear Algebra linear combinations help

porschedude
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The linear combinations of v=(a,b) and w=(c,d) fill the plane unless _____.
Find four vectors u, v, w, z with four components each so that their combinations cu+dv+ew+fz produce all vectors (b1, b2, b3, b4) in four dimensional space.

I think that the first part of the answer, that fills the blank, is unless v is a scalar multiple of w, or vice versa.

But as far as the second part of the question, I have no idea what it is even asking. Are b1, etc. referencing the first part of the question? Or is it just asking to write vectors that have all zero components except b1 etc. Any help is much appreciated?
 
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The first answer looks fine. I THINK the second one is just asking you to write down four vectors that span R^4. Like u=(1,0,0,0) might be a good choice for the first one. Can you give me a v, w and z that span together with u?
 
That's what I thought it might mean v=(0,1,0,0), w=(0,0,1,0), z=(0,0,01), but that seems too simple. It's listed in the book as a challenge problems
 
porschedude said:
That's what I thought it might mean v=(0,1,0,0), w=(0,0,1,0), z=(0,0,01), but that seems too simple. It's listed in the book as a challenge problems

Sure. But I can't think what else it might mean. It certainly can't be referencing any symbols in the first part, since the first part is about R^2.
 
Alright, thanks for the help,
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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