Linearising Cosine: Taking Roots of Equation

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Homework Statement


Linearise the following equation I(theta) = (I1 – I2 ) cos (2theta) + I2
where I1 and I2 are constants.

Homework Equations


I(theta) = (I1 – I2 ) cos (2theta) + I2

The Attempt at a Solution


Not sure how to linearise the cos(2theta). Have tried trig identities, would the best option be to take roots of both sides of the equation?
 
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Hi Agrajag, what do you mean by linearize? I usually understand "linearization" to mean: find the closest linear approximation to the given curve. This can be found by taking the derivative at a point to be the slope of a line that goes through that same point. This line is your linearization.
 
friendbobbiny said:
Hi Agrajag, what do you mean by linearize? I usually understand "linearization" to mean: find the closest linear approximation to the given curve. This can be found by taking the derivative at a point to be the slope of a line that goes through that same point. This line is your linearization.

Hi friendbobbiny, the final equation should be in the form y=mx+c where y is I(theta) and x is theta.
 
Agrajag said:
Hi friendbobbiny, the final equation should be in the form y=mx+c where y is I(theta) and x is theta.

In that case, my approach works! Have you read into finding a linearization by taking a derivative at some point of interest (or at any point of interest)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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