Logic gates, inverting output without increasing transistor count

AI Thread Summary
The discussion focuses on optimizing the design of logic gates while minimizing transistor count. The original expression A'.(B+C) was simplified to A+B'.C', with a goal to achieve the output using fewer than ten transistors. A participant inquired about inverting the output after a NOR gate without adding new transistors and suggested the possibility of using an OR gate instead. Ultimately, the problem was resolved by developing a truth table, leading to a simpler solution. The conversation highlights the importance of truth tables in logic gate design and optimization.
sandy.bridge
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Homework Statement


Hello all,
I have the following logic gates:
(A'.(B+C))' which I had reduced to A+B'.C'. I then want use a NAND gate connected to a NOR gate, then connected to an inverted. However, I have been informed that I need not to use ten transistors, and that 8 can get the job done. How exactly can I invert the output after the NOR gate without the addition of new transistors?
 
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Can you use an OR gate instead of NOR + NOT?

Otherwise, draw the arrangement you propose using, and you may be able to spot where you can economize on the number of gates.

B'.C' can be converted to a NOR
 
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Thanks, I managed to get it. It was a lot more simple upon developing and then utilizing a truth table.
 
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