Luminosity in LHC: Engineer's Guide to Understanding

kususe
Messages
22
Reaction score
0
I'm an engineer.
What's luminosity? I don't understand the explanation of Wikipedia.
Why are physics glad if the luminosity grows up in LHC, respect of last year?
 
Physics news on Phys.org
for the second question I think the answer is http://slsbd.web.psi.ch/pub/cas/cas/node38.html"
 
Last edited by a moderator:
kususe said:
I'm an engineer.
What's luminosity? I don't understand the explanation of Wikipedia.

Read this, especially on pages 31-34

http://www.phys.spbu.ru/content/File/Library/studentlectures/schlippe/pp05-07.pdf

Why are physics glad if the luminosity grows up in LHC, respect of last year?

If the luminosity is too low, you are getting very few collisions and thus, very few data. Considering that the probability of finding one of these exotic interaction is very low, and you also need to have very good statistics, you want to have as high of a collision rate as you can to increase your chances. Too low of a luminosity, and it will take months, if not years, to find something, if it is really there.

Zz.
 
Last edited by a moderator:
Thank you.
Question solved.
 
Last edited:

Thread 'Toponium Discovered'

Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
View full post »

Thread 'Dirac-Delta from Normalization of Continuous Eigenfunctions'

I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
View full post »

Similar threads

I Beyond LHC, future particle colliders and lasers
Replies
28
Views
4K
I LHC To Announce Its Lepton Universality Violation Results On Tuesday (20-Dec)
Replies
30
Views
3K
I LHC finishes proton-proton collisions in 2018
2
Replies
57
Views
15K
I How Much Better Will Top and Higgs Mass Measurements Get?
Replies
2
Views
2K
A Interested in the LHC safety assessment - questions about strangelets
Replies
7
Views
2K
Is a Small Space Hadron Collider More Efficient than a Large One?
Replies
26
Views
3K
Why does the LHC need to be more powerful?
Replies
12
Views
2K
I New Naming Rules for Exotic Hadrons at the LHC: LHCb Collaboration Paper (2022)
Replies
7
Views
2K
A W+/W- bosons ratio in proton-proton collision
Replies
5
Views
3K
LHC Experiments: Understanding "Turning On" the Collider
Replies
7
Views
2K

Hot Threads

Recent Insights

Back
Top