Magnetic Field & Electron Speed

AI Thread Summary
To limit the current to 15A using a 120V circuit with 14-gauge copper wire, a length of 812.9 meters is required. The magnetic field generated by wrapping the wire in a circular loop of radius 0.5 meters is calculated to be 49 mT, based on 517 loops of wire. However, an attempt to calculate the speed of electrons moving in a radius of 0.25 meters resulted in an unphysical value of 8.4 x 10^8 m/s, exceeding the speed of light. The calculations for the magnetic field and electron speed need to be reviewed, particularly the application of the relevant physics equations. Clarification on the calculations and potential errors is sought to resolve the discrepancies.
baileya
Messages
20
Reaction score
0

Homework Statement


You have decided to make a home made cyclotron (particle accelerator). You decide to use a household circuit use a 120V, 15 Amp circuit. If 14-gauge copper wire has a resistance per unit length of 3 ohm per 1000ft, what length of wire is required to limit the current to 15A?

Next, your "cyclotron" needs to have a region of constant magnetic field. To create this, you choose to wrap the wire in a circular loop of radius 0.5-m. What is the maximum magnetic field you can create? (you need to figure out the number of loops!)

Finally you inject the electrons into your cyclotron. What is the speed of the electrons if they move in a radius of 0.25-m? If the electrons started from rest, what potential difference is required to generate that speed?

Homework Equations





The Attempt at a Solution


Alright... so I figured out the first parts of the question (812.9 m wire length and magnetic field of 49mT for the r=.5 m wire) but when I tried to determine the electron speed I got a number that's greater than the speed of light.
I determined that the circumference is 1.57 m, which allows for 517 loops of wire. Then using B=(4pi x 10^-7)NI/2r I got that the magnetic field is 1.9 x 10^-2
This means that using v=rqB/m where r=.25m, q=1.6 x 10^-19, B=1.9 x 10^-2, and m=9 x 10^-31)
I got that the speed of the electron is 8.4 x 10^8 m/s
This is way too fast I'm assuming, so can somebody tell me where I went wrong.
 
Physics news on Phys.org
how did you find the length?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top