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## Homework Statement

A long, straight wire carrying a current of 4.00 A is placed along the axis of a cylinder of radius 0.500 m and a length of 3.00 m. Determine the total magnetic flux through the cylinder.

## Homework Equations

Flux = BA

B(long wire) = (((4 * pi) * 10^-7) * I )/ (2 * pi * R)

A(cyclinder) = (2 * pi * r^2) + (2 * pi * r * h)

## The Attempt at a Solution

I = 4

r = .5

h = 3

I tried to solve for B by saying:

B = (((4 * pi) * 10^-7) * 4 )/ (2 * pi * .5)

B = 1.6 * 10^-6

and then A:

A = (2 * pi * .5^2) + (2 * pi * .5 * 3)

A = 10.99

Flux = (1.6 * 10^-6) * 10.99

Flux = 1.75 * 10^-5

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This is incorrect. Not sure what I am doing wrong here. Any help is very much appreciated. This is due tonight at 11pm EST

Thanks much,

Kyle