Magnetic Flux through a Cylinder

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  • Thread starter xxkylexx
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Homework Statement


A long, straight wire carrying a current of 4.00 A is placed along the axis of a cylinder of radius 0.500 m and a length of 3.00 m. Determine the total magnetic flux through the cylinder.

Homework Equations


Flux = BA
B(long wire) = (((4 * pi) * 10^-7) * I )/ (2 * pi * R)
A(cyclinder) = (2 * pi * r^2) + (2 * pi * r * h)

The Attempt at a Solution


I = 4
r = .5
h = 3

I tried to solve for B by saying:
B = (((4 * pi) * 10^-7) * 4 )/ (2 * pi * .5)
B = 1.6 * 10^-6

and then A:
A = (2 * pi * .5^2) + (2 * pi * .5 * 3)
A = 10.99


Flux = (1.6 * 10^-6) * 10.99
Flux = 1.75 * 10^-5


----------------------------


This is incorrect. Not sure what I am doing wrong here. Any help is very much appreciated. This is due tonight at 11pm EST :smile:


Thanks much,
Kyle
 

Answers and Replies

  • #2
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Notice here is asking you to find the total flux through the cylinder. However, the magnetic field lines are always perpendicular to the surface of the cylinder. So even if your calculations are right, it is not acting on the right direction. The final answer is zero
 

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