Magnetic Field and Charged Particle Motion

In summary: So using the right-hand rule I can determine the direction of the force, which is perpendicular to the velocity. But how can I determine the magnitude of the force? Is it simply F=qvB, where q is the charge, v is the velocity, and B is the magnetic field?In summary, the conversation discusses the properties and effects of a magnetic field on a charged particle in motion. It is determined that the force produced by the magnetic field is always perpendicular to the particle's velocity and does not change its speed. The direction of this force can be determined using the right- or left-hand rule, and its magnitude can be calculated using the equation F=qvB, where q is the charge, v is the velocity, and
  • #1
phyvamp
13
0

Homework Statement


Suppose a subatomic particle of mass m kg has kinetic energy K.E. a nJ and is moving southward toward a vertical wall. When the particle is distance d cm from the wall a magnetic field is turned on: it has magnitude b T and points upward. The particle turns westward so it just skims along the wall. Find q, the charge (magnitude and sign) of the particle, in C.

Homework Equations


dF=IdLB
F=qvB

The Attempt at a Solution


I attempt to use 1/2 mv^2 = K.E. to find initial velocity first, but the direction of velocity is changed due to magnetic field. the magnitude of the velocity will change also? and I do not know how to find out the force acted on particle due to magnitude field either. Does K.E.=∫ F*dx from xi=0 to xf=d to find out F works? is this F the same with force due to magnitude field? or actually I need to consider about gravity?
thank you for your help!
 
Physics news on Phys.org
  • #2
What path does the charged particle follow due to the presence of the magnetic field?
 
  • #3
phyvamp said:

Homework Statement


Suppose a subatomic particle of mass m kg has kinetic energy K.E. a nJ and is moving southward toward a vertical wall. When the particle is distance d cm from the wall a magnetic field is turned on: it has magnitude b T and points upward. The particle turns westward so it just skims along the wall. Find q, the charge (magnitude and sign) of the particle, in C.

Homework Equations


dF=IdLB
F=qvB

The Attempt at a Solution


I attempt to use 1/2 mv^2 = K.E. to find initial velocity first, but the direction of velocity is changed due to magnetic field. the magnitude of the velocity will change also? and I do not know how to find out the force acted on particle due to magnitude field either. Does K.E.=∫ F*dx from xi=0 to xf=d to find out F works? is this F the same with force due to magnitude field? or actually I need to consider about gravity?
thank you for your help!
A magnetic field produces a force at right angles to the direction of motion of a moving charge. The particulars are determined by a vector cross product of the velocity and field vectors, or through the application of the right- or left-hand rule.

As is the case for circular motion, which you must have studied previously, the acceleration is at right angles to the motion and so changes the direction of the velocity vector but not its magnitude (speed). So, think about centripetal force and the types of calculations that pertain to it.
 
  • Like
Likes phyvamp
  • #4
gneill said:
A magnetic field produces a force at right angles to the direction of motion of a moving charge. The particulars are determined by a vector cross product of the velocity and field vectors, or through the application of the right- or left-hand rule.

As is the case for circular motion, which you must have studied previously, the acceleration is at right angles to the motion and so changes the direction of the velocity vector but not its magnitude (speed). So, think about centripetal force and the types of calculations that pertain to it.

thank you for the explanation. So magnetic field will not change the magnitude of the velocity generally? or this question just a particular case since acceleration is at right angles to the motion?
 
  • #5
phyvamp said:
thank you for the explanation. So magnetic field will not change the magnitude of the velocity generally? or this question just a particular case since acceleration is at right angles to the motion?
In general a magnetic field won't change the speed of a charged particle moving through it. Any force that a moving charge "feels" due to its interaction with a magnetic field is always perpendicular to its direction of travel. It can change it's direction of travel, but not its speed.

To investigate further it would be helpful to know about the properties of the vector cross product. That's the mathematical approach. You can also investigate the "right hand rule" or "left hand rule" practical embodiments of the cross product properties that are used in practice to determine the direction of the effects.
 
  • #6
gneill said:
In general a magnetic field won't change the speed of a charged particle moving through it. Any force that a moving charge "feels" due to its interaction with a magnetic field is always perpendicular to its direction of travel. It can change it's direction of travel, but not its speed.

To investigate further it would be helpful to know about the properties of the vector cross product. That's the mathematical approach. You can also investigate the "right hand rule" or "left hand rule" practical embodiments of the cross product properties that are used in practice to determine the direction of the effects.

thanks again for the explanation.
 

1. What is magnetism?

Magnetism is a force that is generated by moving electric charges. It is caused by the alignment of electrons in a material, which creates a magnetic field.

2. How is magnetism related to kinetic energy?

Magnetism is related to kinetic energy because it can be used to move objects and perform work. When a magnet attracts or repels another object, kinetic energy is transferred between the two objects.

3. What is the role of magnetism in electricity?

Magnetism plays a crucial role in electricity, as it is the basis for the generation of electricity. Moving electric charges create a magnetic field, and changing magnetic fields can induce an electric current in a conductor.

4. How can magnetism be used in technology?

Magnetism has many practical applications in technology, such as in electric motors, generators, and magnetic storage devices. It is also used in medical imaging, particle accelerators, and many other technologies.

5. How do magnets lose their magnetism?

Magnets can lose their magnetism over time due to exposure to heat, strong magnetic fields, and physical damage. Additionally, some materials, such as iron, can be demagnetized by repeatedly heating and cooling them in a process called thermal demagnetization.

Similar threads

  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
801
  • Introductory Physics Homework Help
Replies
18
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
668
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
7K
  • Introductory Physics Homework Help
Replies
10
Views
3K
  • Introductory Physics Homework Help
Replies
3
Views
749
Back
Top