How Much Current Sustains the Suspended Copper Wire?

AI Thread Summary
A long horizontal wire carrying a current of 48 A induces a magnetic field affecting a parallel copper wire suspended 15 cm below. The magnetic field (B) was initially calculated as 4.2639 * 10^-4 T using the formula μI / 2∏r. However, an arithmetic error was identified, leading to a corrected magnetic field value of 6.4 * 10^-5 T. This corrected value was then used to determine the current in the lower wire, resulting in a final current of 3.19 A. The discussion highlights the importance of accurate calculations in physics problems.
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Homework Statement



A long horizontal wire carries a current of 48 A. A second wire, made of 3.0 mm diameter copper wire and parallel to the first, is kept in suspension magnetically 15 cm below. Determine the magnitude of the current in the lower wire.

Homework Equations



μI / 2∏r

The Attempt at a Solution



B = (1.256*10^-6)(48 A) / (2∏)(.15 m)^2
B = 4.2639 * 10 ^-4 T

B(2∏r) / μ = I

(4.2639 * 10^-4 T)(2∏)(1.5*10^-3 m)/(1.256 * 10^-6)

I = 3.19 A
 

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PeachBanana said:
B = (1.256*10^-6)(48 A) / (2∏)(.15 m)^2
B = 4.2639 * 10 ^-4 T


You made an arithmetic mistake .:wink:

B= [4∏*10^-7]*[48]/(2∏*0.15) = 6.4*10^-5 T
 
Oops! Thank you for that.
 
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