Magnitude and Direction of Electric Field

AI Thread Summary
Two point charges, +3.0 μC at (0, 2 m) and -2.0 μC at the origin, create an electric field that affects a +1.0 x 10^-9 C test charge at various locations. The electric field is calculated using the formula E = kq/(r^2), with adjustments for distance based on the test charge's position. For part C, the user seeks guidance on calculating the force from both charges at the point (1.0 m, 0), requiring the resolution of the electric field components from the +3 μC charge into x and y components. The discussion emphasizes the need to find distances and angles to accurately determine the resultant electric field. The user plans to implement these calculations in their next attempt.
bwilhelm
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Homework Statement


Two point charges are placed on the y-axis. One is +3.0 C and located at position (0, 2 m), the other is -2.0 C and located at the origin. Use the diagram to find the magnitude and direction of the electric field and the force on a +1.0 x 10-9 C test charge placed in the following locations.
a. (0, 1.0 m)
b. (0, -2.0 m)
c. (1.0m, 0)

Homework Equations



E= kq/(r^2)

The Attempt at a Solution


So for part a:
F= (K(3x10^-6)/(1^2) + K(2x10-6)/(1^2))
E= F/(test charge)

Same for part b, but the radius is different.
My question is how do I get part C?
I calculated the force between the -2uc charge and point C, but how do I get the force between the +3uc charge and point C?

Do I need to find the angle?
 

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Find the distance between points ( 0, 2) and (1,0).
Find field at (1,0) due to + 3μC and - 2μC.
Resolve the field due to +3μC into x and y components.
Find the net x component and find the resultant with y component.
 
rl.bhat said:
Find the distance between points ( 0, 2) and (1,0).
Find field at (1,0) due to + 3μC and - 2μC.
Resolve the field due to +3μC into x and y components.
Find the net x component and find the resultant with y component.

Thank you for the reply, i'll try this out tomorrow.
 
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