Magnitude and Direction of Electric Fields

AI Thread Summary
To determine the charge of object A based on the electric field at point P, the formula E = k|q|/d² can be used, where E is the electric field strength, k is Coulomb's constant, q is the charge, and d is the distance from the charge to the point. Given that the electric field at point P is 40.0 N/C directed south, this indicates that object A is negatively charged since the field points towards the charge. The distance from object A to point P is 0.250 m. By rearranging the formula to solve for q, the charge can be calculated as q = E * d² / k. Understanding the relationship between electric fields and point charges is essential for solving similar problems in electrostatics.
sarahaha44
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Hey yall. This is a question from my homework but it's so basic that it's just to help with the concept for me. So the question is this:

A small object A, electrically charged, creates an electric field. At a point P located 0.250 directly north of A, the field has a value of 40.0 directed to the south. What is the charge of object A?

I know there is a formula, is it perhaps E=F/q) E= 2kq/d ? And if it is, what is plugged in for what? Help please!
 
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Tip: a "small object" can be treated as point-like to a good approximation. So try a Google search for "electric field of a point charge".

If you're using a printed textbook, try looking in the index under "Electric field /
Point charge" or something like that.​
 
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