Magnitude of Electric field using superposition principle

AI Thread Summary
The discussion revolves around calculating the electric field at point P due to two charges, +q and -q, using the superposition principle. The user initially miscalculated the distances involved and the components of the electric field vectors. Corrections were suggested regarding the proper use of the Pythagorean theorem to find the hypotenuse distance between the charges and point P. Additionally, the importance of considering the direction of the electric field vectors from both charges was emphasized, as they can cancel each other out. The conversation highlights the need for careful attention to detail in vector components and distance calculations in electric field problems.
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Homework Statement



Two charges, +q and -q, are located in the x-y plane at points (0,+d/2) and (0,-d/2), respectively. Calculate the magnitude of the electric field at point P with the superposition principle.
Data: q=37.0 nanoCoulombs,
d=4.60mm and P at
x=92.0mm.

Homework Equations


E = kQ/r^2
a^2 + b^2 = c^2
sin = o/h


The Attempt at a Solution


I tried to solve this like a normal E field question.
For the +q charge, I got that the E field would be:
( k * -37E-6 (sin2) / .092^2) + ( k * 37E-6 (cos2)
and For the -q charge, I got that the E field would be:
( ( k * -37E-6 (sin2) / .092^2) - ( k * 37E-6 (cos2)
This came out to 2740 N/C (positive b/c it asks for magnitude) but that was wrong. Can someone tell me where I'm going wrong? I attached the diagram.
 

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I understood what you first did,

you first said that you will break up E= Esintheta + Ecostheta, one thing I noticed that in the equation E=kq/r^2 , you used for r = 0.092 you used the x distance for the point p, I suggest you have another look at your figure :

http://img231.imageshack.us/img231/5466/59813260.gif

compare the blue line with the red one , do you still think that the distance between q and p is x (0.092) ?
 
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When I did (.092^2) + (.0023^2), I get that the hypotenuse is .0092...
 
Ah, sorry my mistake, I now get .00847. I will try that. Was the rest of the setup ok? Thanks for your help!
 
Hmmm... that was still wrong. Am I doing something else incorrectly?
 
i think the required distance between q and p should be sqrt((0.092^2) + (0.0023^2)) i did the calculation and i got 0.092028 (when you said it is 0.00847 you didnt take the square root) ..

another thing, I think you probably haven't considered the elecrtic field produced from positive charge and negative charge, have a look at this figure:

http://img402.imageshack.us/img402/7681/95152182.jpg

so your problem should look something like the following:

http://img4.imageshack.us/img4/4996/34194234.gif

notice where r the electric field vectors , find the components of each vectors ,then see whether you will find any compenents that will cancel with each other and pay attention to the directions ..

by the way , i have one question for you , from where you get sin2 and cos2?
 
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