Magnitude of the Electric Field at the Following Distances

AI Thread Summary
The discussion focuses on calculating the electric field at various radial distances from a spherical shell with a uniform charge density. Participants highlight the challenge of adapting formulas for a solid sphere to accommodate the cavity within the shell. The shell theorem is referenced, emphasizing that charge outside a given radius can be ignored, while charge within can be treated as concentrated at the center. Suggestions include using the superposition principle by considering two concentric spheres with opposite charge densities. The conversation concludes with a step-by-step method for finding the electric field by calculating contributions from both spheres and combining them appropriately.
Darkgora

Homework Statement


The figure below shows a spherical shell with uniform volume charge density ρ = 1.87 nC/m3, inner radius a = 15.0 cm, and outer radius b = 2.60a.

[Reference Picture]

What is the magnitude of the electric field at the following radial distances?

Homework Equations


E=k(q/r^2)
E=k(q/R^3)*r^2

The Attempt at a Solution


I only understand how to compute an electric field for a solid sphere. I am unsure how to alter the given equation to compensate for the cavity within the charged spherical shell.
phy 1.png
 
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The shell theorem is used to answer questions like this. It enables one to ignore spherically-distributed charge at distance greater than r from the centre of the sphere, and the rest of the charge can be assumed to be at the centre of the sphere..
 
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Here is an alternative approach. Since you understand the electric field due to a solid sphere, for this problem consider the superposition of the electric fields from two concentric solid spheres, one of radius b and charge density +ρ and one of radius a and charge density -ρ.
 
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kuruman said:
Here is an alternative approach. Since you understand the electric field due to a solid sphere, for this problem consider the superposition of the electric fields from two concentric solid spheres, one of radius b and charge density +ρ and one of radius a and charge density -ρ.

I am unsure how to compute the electric field given charge density, thus I have solved for the total charge enclosed:

Volume of hollow sphere * Charge Density
= 4(pi)/3(.351^3-.13^3) * (1.89e-9)

When I plug this total enclosed charge value into kqr/R^3 and subtract the inner from outer sphere I am not getting the right answer.
 
Darkgora said:
When I plug this total enclosed charge value into kqr/R^3 and subtract the inner from outer sphere I am not getting the right answer.
You missed the point of my suggestion. Follow these steps for the field in parts d -f.
1. Find the field due to a solid sphere of charge density -ρ and radius a at that radius.
2. Find the field due to a solid sphere of charge density +ρ and radius b at that radius.
3. Add the fields (one is positive the other negative).

Reference: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elesph.html
 
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