Man & Dog: DistanceTraveled Ques.

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A man jogs at a speed of 1.5 m/s, while his dog waits for 1.6 seconds before running at 3.8 m/s to catch him. The key to solving the problem lies in determining the distance each has traveled when the dog catches up, ensuring that both have the same distance covered. The dog must cover the distance the man has traveled during the wait time plus the distance while both are moving. The solution requires setting the distances equal to find the point of intersection. Understanding that both the man and dog will have the same distance when the dog catches up is crucial for solving the problem.
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I am having a problem with a question, I am wondering if anyone can help me with it.
A man jogs at a speed of 1.5m/s. His dog waits 1.6s and then takes off running at a speed of 3.8m/s to catch the man. How far will they have each traveled when the dog catches up with the man? Answer in units of m.
 
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You need to show some work before we can help you. As a hint, what quantity must be the same for both the man and the dog when the catches the man up?
 
cristo said:
You need to show some work before we can help you. As a hint, what quantity must be the same for both the man and the dog when the catches the man up?

The acceleration?
 
AraProdieur said:
The acceleration?

No. Think about it like this. Imagine you are walking down the street and your dog is following you. When it catches you up, you are both in the same ______.
 
cristo said:
No. Think about it like this. Imagine you are walking down the street and your dog is following you. When it catches you up, you are both in the same ______.

velocity
 
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