Man Lifts 15kg Bucket from Well: Calculating Depth

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To calculate the depth of the well from which a 15.0 kg bucket is lifted with 3.00 kJ of work done, one must understand the relationship between work, force, and distance. The work done is equal to the force exerted on the bucket multiplied by the distance it is lifted, expressed as Work = Force x Distance. Given that the bucket is lifted at a constant speed, the force equals the weight of the bucket, calculated as F = mg, where g is the acceleration due to gravity. By substituting the values into the equation, the depth of the well can be determined. This approach effectively utilizes the principles of physics to solve the problem.
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If a man lifts a 15.0 kg bucket from a well and does 3.00 kJ of work, how deep is the well? Assume that the speed of the bucket remains constant as it is lifted.
 
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parwana said:
If a man lifts a 15.0 kg bucket from a well and does 3.00 kJ of work, how deep is the well? Assume that the speed of the bucket remains constant as it is lifted.

What is the definition of work? Look it up, and I'm sure you'll be able to solve this without any difficulties.

Further on, think about why constant velocity is mentioned. What are the forces that are acting on the bucket? In what relation are they (because of constant velocity)?
 
Work= Force times change in x
I got it

I used F= ma to find F

then plugged it in the equation to find x
 
Last edited:
parwana said:
F= ma to find F

Its supposed to be mg where g is ur acceleration of free fall.
 

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