Manipulating Limits Algebraically: Solving Tricky Equations

  • Thread starter Thread starter sixstring91
  • Start date Start date
  • Tags Tags
    Limits
sixstring91
Messages
2
Reaction score
0

Homework Statement



Just brushing up on my calculus before I start college, but I'm having difficulty manipulating two different limit equations algebraically (sorry I can't find out how to put these into latex):

1) lim (t->0) {1/[t*sqrt(1+t)]} - (1/t)

2) lim (x->-4) [sqrt(x^2+9) - 5]/(x+4)

The Attempt at a Solution



don't know where to begin on (2), but for (1):

mult (1/t) by sqrt(1+t) to match denominators, left with [1 - sqrt(1+t)]/[t*sqrt(1+t)]

any hints?
 
Physics news on Phys.org
Try multiplying the numerator and denominator by 1+sqrt(1+t). Expand out the numerator and see what happens.
 
For 2), multiply the numerator and denominator by the conjugate of the numerator.
 
Dick said:
Try multiplying the numerator and denominator by 1+sqrt(1+t). Expand out the numerator and see what happens.

Bohrok said:
For 2), multiply the numerator and denominator by the conjugate of the numerator.

Ah, both of you were spot on with the conjugates. Thanks for your help.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top