Manometer water and mercury problem

AI Thread Summary
The discussion revolves around a problem involving a mercury manometer affected by water spillage while measuring pressure in a pipe carrying argon. The key details include a water height of 20 cm and a pressure drop of 101.3 kPa, with mercury levels differing on either side of the manometer. Participants express confusion about the relevance of the manometer type and seek guidance on how to approach the calculations. The general manometer equation is provided as a starting point for solving the problem. Clarification on the impact of the water and the specific calculations needed is requested to progress.
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Homework Statement


Water is spilled into a mercury manometer that was being attached to a pipe carrying argon. The water has a height of 20 cm in the manometer and the pressure drop across the manometer is 101.3 kPa (mercury on left lower than on the right) What is the difference in height for the mercury levels on either side of the manometer tube?


Homework Equations


General manometer eq: P1+rho1*g*d1=p2+rho2*g*d2+rho(fluid)*g*h


The Attempt at a Solution


I'm really stuck. Does it matter what kind of manometer it is? Can someone help me start this problem out. Thank you so much.
 
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Could someone please help me start this? Please.
 
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