Mass is the amount of matter in a material?

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Mass is defined as the amount of matter in a material, typically measured by the number of atoms present. However, two objects can have the same mass despite differing atom types and quantities, as different atoms have varying weights. For example, one object may consist of six lighter atoms, while another may contain three heavier atoms, both yielding the same mass. This highlights that mass is not merely the count of molecules but an inherent property of matter related to its inertia and resistance to motion changes. Understanding mass requires recognizing the complexity of atomic composition rather than a simplistic numerical approach.
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hi

Mass is the amount of matter in a material, and by that we mean a number of atoms . So do two bodies have same amount of mass if they have same amount of atoms ? But don't atoms have different weight based on the type they are ?

cheers
 
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u can have a certain atom weighing 1 in an object A and u have 6 of them
1*6 = 6
u can also have another object B composed of 3 atoms each weighing 2
3*2 = 6
they have 2 ojects with same mass but are composed with different a number and type of atoms
 
"The quantity of matter" in an object is very loose definition of mass. As you realize, mass is not simply the number of molecules in an object, since different molecules have different masses. Better to think of mass as an inherent property of matter that is a measure of its inertia: its ability to resist changes to its motion.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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