Mass of an Object Moving Down a Slope.

AI Thread Summary
To find the magnitude of the resistance force (R) for a skateboarder moving down a slope at a constant speed, the equation mgSinΘ - ma = R is used, where g is 9.8 m/s² and a is 0. Given the slope angle (Θ=5°) and constant speed (5 m/s), the calculation simplifies to m0.854 = R, but the mass (m) is unknown. Without additional information such as the mass of the skateboarder or other parameters, determining R directly is not possible. The discussion emphasizes that mgSinΘ is the best approach without the mass value.
Cailan Emmett
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Hello,

I am trying to find the magnitude of the resistance force of an object moving down a slope.
The question I was given says:
A skateboarder heads down a gentle slope (Θ=5°) at a constant speed of 5m/s. Calculate the magnitude of the resistance force.
Using the equation mgSinΘ - ma = R, (g = 9.8, a = 0) I got as far as m0.854 = R, but I need m to find R.
Is there another equation to find m (the mass of the object)?

Any help would be much appreciated.
 
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R is the resistance force on the object (friction, air resistance etc.).

Basically the forces going in the opposite direction to the skateboard.
 
Cailan Emmett said:
Hello,

I am trying to find the magnitude of the resistance force of an object moving down a slope.
The question I was given says:
A skateboarder heads down a gentle slope (Θ=5°) at a constant speed of 5m/s. Calculate the magnitude of the resistance force.
Using the equation mgSinΘ - ma = R, (g = 9.8, a = 0) I got as far as m0.854 = R, but I need m to find R.
Is there another equation to find m (the mass of the object)?

Any help would be much appreciated.
Distance, Height? Anything else given to you?
 
Coolcatss said:
Distance, Height? Anything else given to you?

Unfortunately no. Only the angle of elevation and speed of the object.
 
Cailan Emmett said:
R is the resistance force on the object

Ah, ok. Then, if you're not given the mass of the object, ##mg \sin \theta## is the best you can do.
 
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PeterDonis said:
Ah, ok. Then, if you're not given the mass of the object, ##mg \sin \theta## is the best you can do.

Okay. Thanks for your help.
 
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