1. The problem statement, all variables and given/known data A 3-kg block is at rest relative to a parabolic dish which rotates at a constant rate about a vertical axis. Knowing that the coefficient of static friction is 0.66 and that r = 2 m, determine the maximum allowable velocity v of the block. Picture attached below 2. Relevant equations F = ma 3. The attempt at a solution I began by drawing a FBD on the mass: W: Weight, pointing vertically downwards N: Normal, pointing perpendicular to the surface f: Friction, pointing 90 degrees clockwise from N. From there I calculated the angle from the origin: y = (2^2)/4 = 1 Θ = tan^-1(1/2), with the adjacent arm being 2, vertical arm being 1, and the hypotenuse being sqrt5 Then I determined that the net force should be horizontally pointed inwards, with the formula: F = mv^2/r So Fy is 0, meaning: (3)(9.81) = 0.66N[1/sqrt(5)] + N[2/sqrt(5)] --> N = (29.43sqrt)/(2.66) Now for Fx: [3v^2]/2 = N[1/sqrt(5)] - 0.66N[2/sqrt(5)] The problem is this resolves to be: [3v^2]/2 = -3.54... which has no solution. So, what am I supposed to do from here?