Match the equation with the Direction Field

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Homework Statement


Which of the following direction fields corresponds to the equation:

y' = y-t

I have attached an image of the direction fields


Homework Equations





The Attempt at a Solution


I get that each arrow represents the slope of the function at that point, but I'm not sure how I'm supposed to match the equation to the direction field without knowing what the function is.

Help is appreciated.
 

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  • math 2214 quiz 2.png
    math 2214 quiz 2.png
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Try looking for straight line solutions, y = at+b.
 
As the derivative is graphically the slope of the tangent line at a given point on the function, at the point (t, y(t)) the direction field should match the value of y'.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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