Max Temp in Ideal Gas Transformation: 2490K

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Again, it's a translation, i don't know if it's 100% accurate in english

Homework Statement



An ideal gas suffers a transformation under the law p=p_0-aV, p_0=10^5 Pa, a=\frac{10^6}{8,3} \frac{Pa}{m^3}. The maximum temperature on this transformation is: ...

A) 2450 K
B) 2500 K
C) can't be calculated (THIS IS NOT THE ANSWER)
D) 2480 K
E) 2490 K
F) 2460 K

Homework Equations



\frac{pV}{T}= ct

The Attempt at a Solution



The attempt? Nill...not even my physics teacher could solve this (private lesson with him). And i really don't have any ideea...

That aV is actually another pressure...
 
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Substitute p(V) from the equation to the ideal gas equation to obtain T(V). For V>0, find max(T) :smile:

EDIT: I think the number of moles of the gas must be given for a numerical value of Tmax.
 
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