Maximise profit knowing manufacturing data

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Homework Help Overview

The discussion revolves around maximizing profit based on manufacturing data involving tables and closets. The original poster presents equations related to resource constraints and profit maximization, indicating a focus on linear programming techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore using systems of equations and the Simplex method to determine optimal production levels. There are considerations about including profit margins for different products and the feasibility of graphical methods given the scale of graphs.

Discussion Status

Participants have provided various approaches, including numerical methods and graphical solutions, while discussing the implications of constraints and conditions. There is an acknowledgment of the challenges with graphical methods, but also a recognition of their potential utility in identifying optimal solutions.

Contextual Notes

Participants note the importance of non-negativity conditions for the variables involved and the complexity introduced by multiple inequalities in the problem setup.

prehisto
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Homework Statement


Hi, this is my data and problem.
http://[ATTACH=full]200209[/ATTACH] [ATTACH=full]200210[/ATTACH]

[h2]Homework Equations[/h2][h2]The Attempt at a Solution[/h2]
So I am thinking that I can use system of equation to get the number of tables and closets for given resources.
0,2x+0,1y=40
0,1x+0,3y=60
1,2x+1,5y=371,4
But this does not include that profit from closets are bigger than from tables.. how can i include that?
 

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I have another Idea , maybe I can solve ir using Simplex method.
0,2x+0,1y<=40
0,1x+0,3y<=60
1,2x+1,5y<=371,4

and maximize 6x+8y ?
 
prehisto said:
I have another Idea , maybe I can solve ir using Simplex method.
0,2x+0,1y<=40
0,1x+0,3y<=60
1,2x+1,5y<=371,4

and maximize 6x+8y ?
Yes, but do not forget the conditions x>=0, y>=0. Also, it has only 2 variables, so can be solved graphically.
 
Ray Vickson said:
Yes, but do not forget the conditions x>=0, y>=0. Also, it has only 2 variables, so can be solved graphically.
Thanks .
it seems that graphically is not such a good idea because of the scale of graphs.
Although it seems that it will be nasty, I will try to do it numerically by pivot point method ( if it is the correct notation).
 
prehisto said:
Thanks .
it seems that graphically is not such a good idea because of the scale of graphs.
Although it seems that it will be nasty, I will try to do it numerically by pivot point method ( if it is the correct notation).
The graphical method works perfectly well when used as intended: it gives you the information about which two of the five inequalities are equalities at the optimum. Then you have two equations in two unknowns to solve, and doing that gives the exact solution. (The 5 inequalities are the 3 functional inequalities and the two non-negativity conditions.)
 

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