Maximizing Function Increase: Understanding Directional Derivatives

Master J
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I have a function of 2 variables. I know it increase most rapidly in the direction of the gradient, but how about in wht direction is it not increasing?

I am thinking that the gradient (dot product)(direction in which it is not increasing) = 0

Any hints?
 
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Well, since you mentioned the word "directional derivative" anyway: you could check for which \vec v
(\vec\nabla f(x, y)) \cdot \vec v < 0
?
 
Yes, it is true that \vector{\nabla f}\cdot \vector v is the directional derivative in the directional derivative in the direction of \vec{v} (for \vec{v} of length 1). And that tells you the derivative is 0 perpendicular to the gradient.

(CompuChip, surely you didn't mean "<"?)
 
Err, no comment? :)
 
That is what is was thinking, since of course cos(pi/2) = 0. So the vector that is at a right angle to the gradient is in the direction of zero increase. But how do I go about finding this vector?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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