Maximizing Transferred Energy between n bodies in linear collisions

AI Thread Summary
The discussion focuses on maximizing the kinetic energy transferred to a mass in a linear collision involving multiple bodies. In the first part, it is determined that for two masses, the optimal mass between them is the geometric mean, specifically ##m_1 = \sqrt{mM}##. The second part suggests a similar relationship for n masses, proposing that each mass should be the geometric mean of its adjacent masses. The challenge lies in formally proving this relationship for n bodies without resorting to proof by contradiction, with suggestions for using mathematical induction or direct derivative methods. The complexity increases with the number of variables, making the proof more intricate.
titansarus
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Homework Statement


My problem has two parts.
1) We have two point masses ##m,M##. and there is another mass ##m_1## between them.They are all aligned in a line. Mass ##M## is moving with speed ##u_1## toward ##m_1## and after collision and all other masses are not moving. we want to find ##m_1## such that the kinetic energy of ##m## get maximum.
2) Now think that we have n masses ##m_1 ,m_2 ,... m_n## between ##m , M##. find ##m_1 , m_2 , ... , m_n## such that the kinetic energy of ##m## get maximum. (elasticity coefficients are ##e_1## and ##e_2## ,... but they are not actually important and you can ignore them i.e. ##e=1##)

physics question 8.png


Homework Equations


In collision between two masses of mass ##m_1## and ##m_2## with elasticity coefficient ##e## moving with speed ##u_1## and ##u_2##, speed of ##v_1## after collision is:
## v_1 = \frac{(m_1-m_2 e)}{m_1+m_2} u_1 + \frac{m_2 e}{m_1 + m_2} u_2 ## (Eq.1)

The Attempt at a Solution


[/B]
The main goal is to maximize ##v## of ##m##. For part 1 if we write the (Eq.1) two times with ##u_1 = 0## for ##M,m_1## and ##m_1,m## we get:

##v_m = 4 ~e~e'~M u_1 (\frac{m_1}{(m+m_1)(M+m_1)})##. If we calculate ##\frac{d}{d~m_1} (v_m) =0## we get ##m_1 =\sqrt {mM}##.

For the second part, I don't know how to formally write a proof but I think the answer will be ##m_i = \sqrt{m_{i-1}m_{i+1}}##. which means that every mass must be the geometric mean of its left and right mass and for ##m_1## we get ##m_1 = \sqrt{M m_2}## and for ##m_n## we get ##m_n = \sqrt{m m_{n-1}}##. I think it is somehow obvious that we must maximize the ##v## in each collision but I can't mathematically prove that. So I want to know how to write a formal proof for this question.
 

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titansarus said:
So I want to know how to write a formal proof for this question.
Suppose you think you have somehow managed to tune all the intermediate masses so as to get the biggest final velocity you can. What if you find three adjacent masses in the sequence that do not fit the expected pattern. What can you deduce?
 
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haruspex said:
Suppose you think you have somehow managed to tune all the intermediate masses so as to get the biggest final velocity you can. What if you find three adjacent masses in the sequence that do not fit the expected pattern. What can you deduce?

Maybe we can say that if this thing happens for ##m_{i-1} , m_{i} , m_{i+1}## and they do not fit the expected pattern, then if we consider a ##v## for ##m_{i-1}##, then the energy (velocity) transferred to ##m_{i+1}## will not be maximum. However, I think maybe there should be a way to solve this without using "Proof by contradiction". Perhaps there is way using "Mathematical Induction" or even a direct proof like the derivative (max-min) proof for 3 mass as I said in the first post. But I cannot write it in a formal way for n-body.
 
titansarus said:
should be a way to solve this without using "Proof by contradiction".
It's a perfectly honourable style of proof.
titansarus said:
direct proof like the derivative (max-min) proof for 3 mass
That could get messy. You have n independent variables, so n differentiations to produce n simultaneous equations.
You could get lucky.
 
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