Maximum Current in AC Circuit Problem

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SUMMARY

The problem involves calculating the peak current through a 200Ω resistor connected to an AC generator with a peak voltage of 10.0V. The peak current (Imax) is determined using Ohm's Law (V=IR), yielding a consistent value of 0.05A for both frequencies of 100Hz and 100kHz. The frequency does not affect the peak current in this scenario, confirming that the solution is straightforward and correct.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Basic knowledge of AC circuits
  • Familiarity with peak voltage and current concepts
  • Concept of resistance in ohms
NEXT STEPS
  • Study the effects of frequency on AC circuit behavior
  • Learn about impedance in AC circuits
  • Explore the relationship between RMS and peak values in AC systems
  • Investigate the role of reactance in AC circuits
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Sandbox.WeC
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Homework Statement


A 200? resistor is connected in series with an AC generator that produces a peak voltage of 10.0V. What is the peak current through the resistor if the frequency of the source is (a) 100Hz and (b) 100kHz


Homework Equations


V=IR


The Attempt at a Solution


I just plugged in the numbers and I arrive at a value of Imax=0.05A for both part a and part b. Is this correct? I am just uncertain if the question is only trying to lead me astray with the frequency values as they do not seem to play a part in this solution.
 
Last edited:
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Hi Sandbox.WeC, welcome to Physics Forums.

You are correct.
 
Thanks a lot. This question just seemed... Overly simple.
 

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