Maximum Parallel Force of an Object

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Homework Help Overview

The problem involves a 7.5 kg object on a horizontal surface, focusing on the maximum parallel force that can be applied without causing motion, considering static and kinetic friction coefficients.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between the coefficients of friction and the normal force to determine the maximum parallel force. Some participants question the necessity of the kinetic friction coefficient in this context.

Discussion Status

The discussion is exploring the correct application of the static friction coefficient and the normal force. Participants are clarifying the values and relationships involved, with some guidance provided on focusing solely on static friction for the problem at hand.

Contextual Notes

There is a correction regarding the normal force value, with the weight of the object being recalculated. The original poster expresses uncertainty about the formulas and their application.

ch3570r
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"For a 7.5 kg object on a horizontal surface that has a coefficient of static friction where us = 1.0, and a coefficient of kinetic friction where uk = 0.8, the maximum parallel force which will not set the object in motion is?"

a) 23.5 N
b) 51.2 N
c) 60.0 N
d) 73.5 N
e) 81.3 N

This is the first problem I've ever done with the coefficient of static and kinetic friction. I have these formulas; F fr = ukFN; Fmax = usFN

Im not sure if that's all I need. I do know that the Normal force (FN) is 71.8, but I am not sure how to go about finding the "max parallel force". If I solve for "Fmax" I get 71.8, but that leaves out the coefficient of static friction. I think I need help
 
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You want to keep your object stationary, correct? So you don't even need the coefficient of kinetic friction at all.
 
well, yea, I guess I don't need the coefficient of kinetic friction.
 
hold on, I was mistaken when I said 71.8 was the normal force. 7.5 * g = 73.5...which is the weight = FN. then, FN * 1 = FN, which is 73.5.

Thanks for the help moose
 

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