grepecs
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Homework Statement
[/B]
Calculate \widehat{Y^{2}}
(i.e., the mean of the square of Y.
Homework Equations
Y=\sum_{k=0}^{N-1}y_{k}
where
y_{k}=e^{-\gamma t}e^{\gamma \tau k}G_{k}
and
t=N\tau
The quantities y_{k} (or G_{k}) are statistically independent.
The Attempt at a Solution
\widehat{Y^{2}}=\widehat{G^{2}}e^{-2\gamma t}\sum_{k=0}^{N-1}e^{2\gamma \tau k}=\widehat{G^{2}}e^{-2\gamma t}(\ \frac{1-e^{2\gamma t}}{1-e^{2\gamma \tau}} )
However, the correct answer should be
\widehat{Y^{2}}=\widehat{G^{2}}\frac{1}{2\gamma\tau} (\ 1-e^{-2\gamma \tau} )
so it seems like I'm doing something wrong, or is it possible to somehow simplify my answer in order to get the correct one?