Mechanical energy required each cycle to operate the refrigerator

AI Thread Summary
The discussion revolves around calculating the mechanical energy required for a refrigerator with a coefficient of performance of 2.16, which absorbs 3.435×10^4 J of heat from a cold reservoir. The user initially struggles with the equations to determine the heat discarded to the hot reservoir and the work needed for the refrigeration cycle. It is clarified that the heat discarded includes both the heat absorbed and the work input to the system. The user ultimately resolves the problem independently and suggests that threads can be marked as solved by editing the title. The conversation highlights the principles of energy transfer in refrigeration systems.
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MODS close this thread down i figured out the answer myself

Homework Statement


A refrigerator has a coefficient of performance of 2.16. Each cycle it absorbs an amount of heat equal to 3.435×104 J from the cold reservoir.

i need to find a) the mechanical energy required each cycle to operate the refrigerator.
b)during each cycle how much heat is discarded to the high temperature reservoir.

Homework Equations


e = W/Qh; e=1+(Qc/Qh)

The Attempt at a Solution



i used the formula in b and apparently it isn't the answer. i also tried using 1-(Qc/Qh) to find Qh. it still didn't work. any other ideas?

thanks
 
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Well, the concept of a refridgerator is a device that moves energy from a cold reservoir to a hot reservoir. So, from this, you know the heat discarded in the hot reservoir has to be at least that removed from the cold reservoir. But you have to remember that you also have to put work into the system in order to get the heat to move from cold to hot, so there will be extra energy discarded into the hot reservoir that will be equal to the work put in. So can you find the total energy being dumped into the hot reservoir from this information?
 
wgd9891 said:
MODS close this thread down i figured out the answer myself

The moderators aren't generally watching all these threads. I believe the local custom is that, if you are satisfied with the resolution of your problem, you can edit your thread title by adding [SOLVED] at the beginning.
 
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