Mechanical System for Lifting and Lowering Weight

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SUMMARY

The discussion focuses on selecting a 115 VAC motor capable of lifting and lowering a load of 150 lbs at a constant speed of 6 inches per second. Key calculations include determining the motor shaft power using the formula Power = weight * g * vel, where weight is 150 lbs, g is 9.81 m/s², and velocity is 6 inches/second. A gearbox is necessary to achieve the desired speed, with a typical motor running at 1750 RPM. Additionally, a variable frequency drive (VFD) is recommended for speed tuning.

PREREQUISITES
  • Understanding of basic physics principles, including force and acceleration.
  • Familiarity with motor specifications, particularly 115 VAC motors.
  • Knowledge of gear reduction calculations and their application in motor systems.
  • Experience with variable frequency drives (VFDs) for motor speed control.
NEXT STEPS
  • Research motor shaft power calculations for different load weights.
  • Explore gearbox options suitable for 115 VAC motors and their specifications.
  • Learn about variable frequency drive (VFD) setup and configuration for motor control.
  • Investigate pulley systems and their impact on motor performance and speed regulation.
USEFUL FOR

Engineers, hobbyists, and technicians involved in mechanical design, particularly those working with motor-driven lifting systems and automation projects.

omalleyt
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Hi, I am looking for a 115 VAC motor (able to be plugged into an ordinary power outlet) that is capable of raising and lowering a load of up to 150 lbs. (attached to a cable and a pulley) at the speed of 6 inches per second. I want the speed to remain constant even if the load changes. How can I turn this into motor specifications? Also, given the low speed, will I need to use a gearbox with this motor and if so what could I use? Also anyone who could help me out in selecting/recommending parts for this system I would be eternally grateful. Thanks for any help.
 
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OK, here are a few starters:

Compute the motor shaft power:

Power = weight * g * vel

weight = 150 lb
g = acceleration due to gravity 9.81 m//s^2
vel = velocity = 6 inch / sec

watch your units.

Now if you put a pulley of radius rp on the shaft, the angular speed is:

angular speed pulley = vel / rp.

If the motor nominal speed is: rpm_motor, the gear reduction is:

gear reduction = rpm_motor / angular speed pulley.

I would also recommend a small, low end VFD so you can tune the speed.
 
Good answer, Edge.
Just to simplify things, though... any normal 115VAC motor that I've seen runs at 1750rpm. That should eliminate one variable.
 

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