Mechanics of materials centroidal question

AI Thread Summary
To find the neutral axis and area centroid of a beam measuring 12 cm wide and 10 cm long, the neutral axis is calculated at 5 cm (h/2). However, there is confusion regarding the area centroid, which is suggested to be at h/4 instead of h/2. Under pure bending conditions, the neutral axis coincides with the centroidal axis, but this may differ when axial loads are involved. The discussion highlights the importance of understanding these concepts and encourages verifying the information against reliable sources. Clarifying these fundamentals is essential for accurate problem-solving in mechanics of materials.
EITintraining
Messages
2
Reaction score
0

Homework Statement


a beam is 12 cm wide and 10 cm long. Find the neutral axis, the area centroid and the distance between them.


Homework Equations


Yc=h/2


The Attempt at a Solution


Yc=10/2=5 cm.
I can't seem to find the area centroid of a rectangle. Any help? Thanks!
 
Physics news on Phys.org
Your question isn't clear to me. Do you mean "beam section"? The neutral axis would be a neutral plane, depending on the direction of loading. On the other hand, it seems a very trivial question. What do you think the answer is? If you were answering this in an exam, and had 15 seconds to answer it, what would you say to get a possible mark?
 
Well I thought that the answer would be the same for the neutral axis as for the area centroid, h/2. But the answer in the back says the area centroid is actually h/4. So the area centroid is half of the distance from the neutral axis?
 
There is a proof (in my strength of materials book) that, under pure bending, the neutral axis is coincident with the centroidal axis. The circumstance in which this is not the case is when there is a combination of axial load and bending, The book could be wrong, as many authors in this forum will attest. On the other hand, the question could be a clumsy attempt to get you to look hard at the fundamentals. See if you can find that proof, and then go and teach it to an interested friend.
 

Similar threads

Back
Top