Solving Mechanics Questions: Cyclists A & B, Fly

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Cyclists A and B start 70 km apart, cycling towards each other at speeds of 15 km/hr and 20 km/hr, respectively. The time until they meet can be calculated using their combined velocities, which total 35 km/hr, leading to a meeting time of 2 hours. The displacement of Cyclist A will be 30 km, while Cyclist B will cover 40 km by the time they meet. The fly, traveling at 30 km/hr, will continuously fly back and forth between the two cyclists until they meet, covering a total distance of 60 km. The problem emphasizes the use of constant velocity equations to determine the meeting point and distances traveled.
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Homework Statement



Two cyclists, A and B, have displacements 0 Km and 70 Km, respectively. At t = 0 they begin to cycle towards each other with velocities 15 Km/hr and 20 Km/hr, respectively. At the same time, a fly that was sitting on A starts flying towards B with a velocity of 30 Km/hr. As soon as the fly reaches B it immediately turns around and flies towards A, and so on until A and B meet.

a) What will the displacement of the two cyclists and the fly be when all three meet?

b) What will be the distance traveled by the fly?


Homework Equations



x = ut + 0.5at^2
v^2 = u^2 + 2as
v= at+u

The Attempt at a Solution



attempted a method of graphing but failed and attempted fill in variables in equations but failed again
 
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There is no acceleration in this problem. The two cyclists move with constant velocities.
Try to find out when will they meet. The equations of motions are just
d1=v1*t
d2=v2*t
with the distances measured from A and B respectively.
What is d1+d2 when they meet?
 

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