Minimum Rate of Rocket Fuel Consumption

AI Thread Summary
To determine the minimum rate of fuel consumption for a rocket with an exhaust speed of 8.0 km/s and a required vertical acceleration of 8.0 m/s², the net force must be calculated using F = ma, resulting in a thrust requirement of 4.8x10^7 N. The thrust is then divided by the exhaust speed to find the fuel consumption rate, yielding 6000 kg/s. However, the initial calculation is incorrect because it considers net force instead of total thrust, which must account for both the weight of the rocket and the required acceleration. The correct approach involves applying Newton's Second Law to include the rocket's weight in the thrust calculation. This highlights the importance of accurately distinguishing between net force and thrust in rocket physics.
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Homework Statement



A rocket which has an exhaust speed of 8.0 km/s is to have a vertical acceleration of 8.0 m/s2. If the initial mass of the rocket is 6.0x106 kg, at what minimum rate must the rocket consume fuel?

Homework Equations



F = ma
F = RVREL

The Attempt at a Solution



F = (6.0x106 kg)(8.0 m/s2) = 4.8x107 N

R = (4.8x107 N) / (8000 m/s) = 6000 kg/s.


The back of the book tells me this answer is wrong. I would appreciate any insight into the error(s) I am making.

Thank you!
 
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I think you must apply Newton's Second Law to the rocket as it lifts off. Your F value is F(net) and not the actual thrust produced by the rocket motor.
 
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