Miscellaneous Chemistry Problems from 2004 Australian NQE

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The discussion revolves around solving various chemistry problems from the 2004 Australian NQE. The first problem addresses John Dalton's incorrect atomic mass assignment for nitrogen based on his misunderstanding of ammonia's formula, leading to a proposed atomic mass of 16. The second problem involves determining the oxidation state of thallium in a compound with a composition of 89.5% Tl and 10.5% O, concluding that thallium has a +3 oxidation state. The third problem discusses the effect of adding helium gas to an equilibrium involving phosphorus pentachloride, with participants debating whether it shifts the equilibrium position towards more PCl3 or PCl5, ultimately revealing confusion about the correct answer. The final problem examines the molecular formula C10H20O2 to identify which class of compounds it cannot belong to, with participants exploring various organic chemistry classifications. Overall, the thread highlights the complexities and misunderstandings in solving chemistry problems.
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Question 1:

Homework Statement


In the early years of the nineteenth century, John published a list of atomic masses. One experiment on which it was based involved measuring the composition by mass of ammonia. By assigning hydrogen a mass of 1 unit and using the chemical formula for ammonia, he could deduce the atomic mass of nitrogen.

Unfortunately, he incorrectly believed that the formula for ammonia was NH. What atomic
mass did he propose for nitrogen on the basis of this formula?

Homework Equations


None?

The Attempt at a Solution


Molar Mass of NH3 = 17
Thinking H is 1, and the formula is NH then
N = 16? (Except this is wrong...)

Question 2

Homework Statement


A brown-black compound of thallium was found to contain 89.5% Tl and 10.5% O. What is
the oxidation number of thallium in this compound?

Homework Equations


None again?

The Attempt at a Solution


204.4 / 89.5 = 2.28
16 / 10.5 = 1.52
2.28 x 2 = 4.5 ish
1.52 x 3 = 4.5 ish

so 3 oxygens to 2 thalliums...so 3+
but I am pretty sure that's not how you do it...its the right answer though...

Question 3

Homework Statement


A sample of phosphorus pentachloride is placed in a sealed container, where it decomposes into phosphorus trichloride and chlorine gas.

Once the mixture is at equilibrium, a small quantity of helium gas is added, at constant pressure and temperature, and the mixture is allowed to return to equilibrium. Which of the following best describes the second equilibrium position with respect to the first?

A - The second equilibrium position is the same as the first, because helium is much
lighter than any of the other molecules in the container and will have a negligible
effect on the reaction.
B - The second equilibrium position is the same as the first, because helium does not
react with any of the other molecules in the container.
C - The second equilibrium position has more PCl3 than the first.
D - The second equilibrium position has more PCl5 than the first.
E - It is impossible to tell what will happen without knowing the equilibrium constant
for this reaction.

Homework Equations


PCl5 (g) <---> PCl3 (g) + Cl2 (g)

The Attempt at a Solution


Addition of helium would increase the number of gas particles and the system would then react to the left in order to decrease the increased pressure.
So I would choose D, except the answer was C

Question 4:

Homework Statement


Q14 An unknown compound was discovered to have molecular formula C10H20O2. To which of the following classes of compounds could this unknown not belong?

A - alkynes
B - alkenes
C - alcohols
D - esters
E - ethers

Homework Equations


Alkynes = CnH2n-2
Alkenes = CnH2n

The Attempt at a Solution


It could be a decene-diol, so A and C would work.
And i wasn't sure about the rest (I wasn't sure what a ester or ether was ><)
 
Physics news on Phys.org
1. Remember in NH3, so the actual masses are 14 (N) and 3 (H), but John (Dalton, I presume to one is referring) used the formula NH. The masses should be 14 + 3 = 17, but changing the basis by dividing by 3 to make mass of 3H to be 1 would give 14/3 + 3/3 = 17/3.

So three H was assigned 1, and the remaining mass 14 would be assigned 14/3.

http://en.wikipedia.org/wiki/John_Dalton

2. For the Tl oxide compound, assume a given mass, e.g. 100 g, which would give 89.5 g of Tl and 10.5 g of O. Divide each quantity by the respective atomic mass, which yields the number of moles, and then find the formula that gives both values of moles as integers.

3. I would expect the He to tend to increase pressure and push the equilibrium to favor more PCl5 - which occupies less volume.

4. http://en.wikipedia.org/wiki/Organic_compound (See ester)

Perhaps chemistree or other chemistry guru will drop into assist.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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