Mom of Special Needs High School Student NEEDS HELP

AI Thread Summary
The discussion centers on helping a mother assist her 14-year-old autistic son with a physics problem involving relative velocity. The problem involves calculating the resulting velocity of a boat paddling upstream against a stream's current. Key points include understanding that velocities are vector quantities and how to assign negative and positive values based on direction. Several users provided formulas and resources to clarify the concept of relative velocity, emphasizing the importance of orientation in calculations. The mother expressed gratitude for the support and resources shared, which will aid her in helping her son with his studies.
kuliraga
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An example of the work he's trying to do is:


1. A stream's current has a velocity of 10 km/hr. You and a friend are trying to paddle upstream at 6 kn/hr. What is the resulting velocity.



2. My problem is that I cannot find the formula or equation that he needs to figure out the problem.



3. There has been no attempt at a solution.


My son is 14, Autistic, and a freshman in high school. It's been seventeen years since I took physics and I just don't remember the information well enough to help him. He's pretty savant-ish when it comes to math. If he has the formula, he can do the work.

Please help us.

Christina
 
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Draw a picture, it always helps when doing physics problems.

Basically you have a stream traveling down at 10km/hr(we well call it -10 km/hr because it is going down) and you are going up at 6 km/hr, the resulting velocity would be the sum of the 2. So -10 km/hr + 6 km/hr = -4 km/hr or 4 km/hr [with the stream].
 
so, basically it's this formula:

velocity relative to x = velocity of a relative to x + velocity of b relative to x

except when you have velocities in opposite directions one of the values is negative. How do you decide which one is negative?
 
You just pick really, unless it tells you the direction the stream is traveling(N, E, S, W, left or right). If it just says there is a stream you just pick. Or you can just subtract the 2 positive values for the same result.
 
Welcome to PhysicsForums, Christina

Velocities are vector quantities (magnitude and direction).

Is 6 kn/hr supposed to be 6 km/hr? or is kn = knots. There's a difference.

Upstream is opposite downstream, so one could take downstream as negative and adding the velocities, -10 km/hr + 6 km/hr = - 4 km/hr, so the net vecocity of the craft is 4 km/hr downstream.

The significance of the + or - signs has to do with orientation.

This site might be of use - http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html

Specifically for the current problem:

Vectors - http://hyperphysics.phy-astr.gsu.edu/hbase/vect.html

Boat in current - http://hyperphysics.phy-astr.gsu.edu/hbase/boatc.html

Velocity - http://hyperphysics.phy-astr.gsu.edu/hbase/vel2.html

Relative velocity - http://hyperphysics.phy-astr.gsu.edu/hbase/relmot.html
 
Astronuc said:
Welcome to PhysicsForums, Christina

Velocities are vector quantities (magnitude and direction).

Is 6 kn/hr supposed to be 6 km/hr? or is kn = knots. There's a difference.

Upstream is opposite downstream, so one could take downstream as negative and adding the velocities, -10 km/hr + 6 km/hr = - 4 km/hr, so the net vecocity of the craft is 4 km/hr downstream.

The significance of the + or - signs has to do with orientation.

This site might be of use - http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html

Specifically for the current problem:

Vectors - http://hyperphysics.phy-astr.gsu.edu/hbase/vect.html

Boat in current - http://hyperphysics.phy-astr.gsu.edu/hbase/boatc.html

Velocity - http://hyperphysics.phy-astr.gsu.edu/hbase/vel2.html

Relative velocity - http://hyperphysics.phy-astr.gsu.edu/hbase/relmot.html

Thank you thank you thank you! both of you have been very helpful, but these links are priceless ... just what I needed to be able to help him with his work. I can't tell you how grateful I am. Thanks again!
 
kuliraga said:
I can't tell you how grateful I am. Thanks again!
You just did, and you are welcome. Good luck with your son.
 
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