Moment of a Distributed Load on Beam, Scanned work and Diagram.

AI Thread Summary
The discussion focuses on determining the forces of reaction for a beam under a distributed load. A user shared their attempt at solving the problem, including a scanned diagram. Feedback highlighted a misunderstanding regarding the calculation of the resultant load from a triangularly distributed load, emphasizing that it does not equal 1350 lbs and that the resultant acts at the centroid. The importance of correctly identifying the centroid's location for accurate moment calculations was also stressed. Accurate calculations are crucial for solving problems involving distributed loads on beams.
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Homework Statement


Determine the forces of reaction.

Homework Equations



SUM of Y forces=0
SUM OF FORCES ABOUT POINT B = 0

The Attempt at a Solution


My attempt is in the link, I scanned the diagram along with my work.
Thanks for the feedback, appreciated.

http://imgur.com/i3cB2 <-----

Link
 
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hello,

When calculating moments, why did you take length of 22,5 ft for force 1350?
 
The total load from the triangularly distributed load is not 1350 lbs. Recalculate that load, and please note that the resultant load of a triangularly distributed load acts at the centroid of that triangle (which is not at its center).
 

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