Moment of a rod of varying thickness

AI Thread Summary
The discussion revolves around calculating the center of gravity of a cylindrical steel shaft that has been altered in thickness. The shaft has a radius of 2 cm for a length of 30 cm and is reduced to 1 cm for the last 20 cm. Participants clarify the problem statement and suggest a method to solve it by calculating the mass of each section based on volume and density. They emphasize that the density will cancel out in the final calculations, simplifying the process. The conversation highlights the importance of understanding the geometry and mass distribution to find the center of gravity accurately.
lordsnowbrood
Messages
8
Reaction score
0

Homework Statement



Q A cylindrical steel shaft of radius 2cm and long is turned upside down on a lathe to one half its radius for a distance of 20cm from one end find the distance of its centre of gravity from the thicker end.?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org


lordsnowbrood said:

Homework Statement



Q A cylindrical steel shaft of radius 2cm and long is turned upside down on a lathe to one half its radius for a distance of 20cm from one end find the distance of its centre of gravity from the thicker end.?

Homework Equations




anticlockwise moment=clockwise moment

The Attempt at a Solution

i don't get the question so can anyone help solve this
 


Hey,
Welcome to PF.

In the second line, is there a typing mistake?

I think you have not copied the question in its exact language , which is causing some confusion (especially the grammer.)

Can you retype it?
 
welcome to pf!

hi lordsnowbrood! welcome to pf! :smile:
lordsnowbrood said:
Q A cylindrical steel shaft of radius 2cm and long is turned upside down on a lathe to one half its radius for a distance of 20cm from one end find the distance of its centre of gravity from the thicker end.?

(you missed out the length … let's call it L :wink:)

do you mean that it has radius 2 cm for length L - 20 cm, and radius 1 cm for length 20 cm ?

if so, find the mass of each part, pretend it's concentrated at the centre of mass (of that part), and then use the usual formula for two masses :smile:
 


tiny-tim said:
hi lordsnowbrood! welcome to pf! :smile:


(you missed out the length … let's call it L :wink:)

do you mean that it has radius 2 cm for length L - 20 cm, and radius 1 cm for length 20 cm ?

if so, find the mass of each part, pretend it's concentrated at the centre of mass (of that part), and then use the usual formula for two masses :smile:

yes you are right.. but how to find mass??
 
Last edited by a moderator:


emailanmol said:
Hey,
Welcome to PF.

In the second line, is there a typing mistake?

I think you have not copied the question in its exact language , which is causing some confusion (especially the grammer.)

Can you retype it?

no mistakes buddy i copied it from my book Abbott physics
 
lordsnowbrood said:
yes u are right.. but how to find mass??

call the density "ρ" … it'll cancel out at the end :smile:
 


lordsnowbrood said:
no mistakes buddy i copied it from my book Abbott physics

Wow! That must be Physics by Abbott and Costello then :smile:
 


I think you have not copied the question in its exact language , which is causing some confusion (especially the grammer.)
Can you retype it?
GRAMMAR
 
  • #10
lordsnowbrood said:

Homework Statement



Q A cylindrical steel shaft of radius 2cm and 50cm long is turned upside down on a lathe to one half its radius for a distance of 20cm from one end find the distance of its centre of gravity from the thicker end.?

Homework Equations





The Attempt at a Solution

i have made the changes can anyone now solve it
 
  • #11


gneill said:
Wow! That must be Physics by Abbott and Costello then :smile:
well it is a blue book published by heinemann and the author is abbott only
 
  • #12
hi lordsnowbrood! :smile:
lordsnowbrood said:
i have made the changes can anyone now solve it

yes, you can solve it! :wink:

find the mass of each part, pretend it's concentrated at the centre of mass (of that part), and then use the usual formula for two masses …

show us what you get :smile:
 
  • #13
tiny-tim said:
hi lordsnowbrood! :smile:


yes, you can solve it! :wink:

find the mass of each part, pretend it's concentrated at the centre of mass (of that part), and then use the usual formula for two masses …

show us what you get :smile:

how could i find the mass man ?? can u help me with that i can find volume but how to find mass in such question got no clue buddy
 
  • #14
lordsnowbrood said:
how could i find the mass man ?? can u help me with that i can find volume but how to find mass …

call the density "ρ" … it'll cancel out at the end :smile:
 
  • #15
tiny-tim said:
call the density "ρ" … it'll cancel out at the end :smile:

could u please solve it coz i cant?
 
  • #16
general strategy: write out the general formula first, then write it out again with the numbers in

(that's why the homework template has that section on Equations! :wink:
)​

sooo …

i] what is the general formula for the volume of a cylinder?

ii] what are the volumes of these two cyliners?

iii] what are the positions of their centres of mass (from the end of the large cyiinder)?

iv] multiply by ρ to get the masses

v] what is the general formula of the position of the centre of mass of two masses?

vi] apply that formula (ρ will cancel) :smile:
 

Similar threads

Replies
9
Views
2K
Replies
4
Views
11K
Replies
3
Views
2K
Replies
8
Views
3K
Replies
26
Views
5K
Replies
3
Views
4K
Back
Top