Moments -- Rods & weights welded together & hanging at an angle

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Homework Help Overview

The discussion revolves around a problem involving two uniform rods welded together, forming a right angle, and suspended from a hinge. The original poster is attempting to analyze the forces and moments acting on the system to determine the angle that one of the rods makes with the vertical while in equilibrium.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster questions the accuracy of their force diagram and seeks clarification on the forces involved beyond the weights of the rods. Participants are prompted to consider the location of the center of mass for the rods and how it affects the force diagram.

Discussion Status

Participants are actively engaging in clarifying the assumptions made in the original poster's force diagram. There is a focus on understanding the correct placement of the center of mass for the rods, with some guidance being offered regarding the implications of its position on the overall analysis.

Contextual Notes

The original poster has attached an image of their force diagram, which is under scrutiny for its accuracy. The discussion highlights the need to reconsider the assumptions made about the center of mass in relation to the hinge point.

nazz
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2 uniform roods each or weight W and length L are welded together so that angel ABC is 90, the two rods are hanging in equilibrium from a fixed loin at A by a hinge which allows the rods to swing in a vertical plane. by taking the moments about the hinge find the angle that AB makes with the vertical.

Question is my force diagram correct or what are the forces involved besides weights ?

please have a look at my force diagram, attached image
 

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Your diagram is drawn as though the centre of mass of rod BC is vertically below A. That will not be the case.
 
so what is right force diagram ?
 
nazz said:
so what is right force diagram ?
Rod AB has a centre of mass to the right of A. Where does the centre of mass of BC need to be for the centre of mass of ABC to be directly below A?
 

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