Momentum Thrust of an Over-Expanded Rocket Nozzle

AI Thread Summary
Understanding momentum thrust in an over-expanded rocket nozzle involves recognizing that traditional isentropic flow equations do not apply due to the presence of normal shocks. The key question is whether the exit velocity is taken as the maximum velocity before the shock or the velocity downstream of the shock. The argument presented suggests that since supersonic flow cannot communicate upstream, the exit velocity should be the maximum attained before the shock. However, it is also noted that analyzing forces on the nozzle or applying conservation of total momentum are valid approaches to determine the exit velocity. Ultimately, the final exit velocity after the nozzle is crucial for calculating momentum thrust.
BrandonBerchtold
Messages
46
Reaction score
6
TL;DR Summary
Momentum Thrust of Over-Expanded Rocket Nozzle
Hi All,
I'm trying to get a better understanding of the momentum thrust given by an over-expanded rocket nozzle (I realize this case voids the isentropic flow assumption used for the 1D isentropic gas expansion equations typically used for rocket engine design since the normal shock is not an isentropic process, but figuring out how momentum works in a supersonic flow is really messing with my brain right now).

Momentum thrust is given by the mass flow rate of propellants times the exit plane velocity, so when the flow mach number plot looks like the image below, what velocity is used as the "exit velocity"? Is the nozzle assumed to stop right before the normal shock, therefore using the maximum attained flow velocity before the shock as the "exit velocity", or is the exit velocity taken as the velocity across the exit plane downstream of the normal shock?

My reasoning is that since the flow is supersonic, no information may travel upstream, so if the flow slows down within the nozzle due to a shock, it can't really affect the nozzle walls upstream of the shock, therefore the exit velocity would be the max velocity before the normal shock. Is my reasoning incorrect?

View attachment 272099 [Source: https://www.mas.bg.ac.rs/_media/istrazivanje/fme/vol40/3/03_vzmijanovic.pdf]

1604447848878.png
 
Last edited by a moderator:
Physics news on Phys.org
There are two ways to study this:

- by forces on the nozzle. Probably the more complicated way.
- by conservation of total momentum. Only the final exit velocity (after the nozzle) matters - and the speed of surrounding air if it gets accelerated backwards.
 
Due to the constant never ending supply of "cool stuff" happening in Aerospace these days I'm creating this thread to consolidate posts every time something new comes along. Please feel free to add random information if its relevant. So to start things off here is the SpaceX Dragon launch coming up shortly, I'll be following up afterwards to see how it all goes. :smile: https://blogs.nasa.gov/spacex/
Back
Top