MOSFET input Voltage for saturation region

AI Thread Summary
To determine the minimum input voltage (VIN) for a MOSFET to be in the saturation region, the relationship VDS > VGS - VT is essential. Given the parameters VS+ = 1.0 V, VS- = -1.0 V, and VT = 0.5 V, the calculations show that VDS equals 2 V. The correct condition for saturation requires VGS to be greater than VT, leading to the conclusion that VIN must be -0.5 V to satisfy this condition. The range for VIN is thus established between -0.5 V and 1.5 V. Understanding these relationships is crucial for those learning electrical engineering.
Piyush Gupta
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I'm trying to solve for the minimum vIN such that MOSFET is in the saturation region. Here are the given parameters
VS+ = 1.0 V
VS- = - 1.0 V
VT = 0.5 V

In order to enter saturation I know that VDS > VGS - VT

VGS = VIN - VS-

VDS = Vs+ - Vs-, which is 2 V

Which means
2V > VIN - VS- - VT
2V > VIN - (- 1.0 V) - 0.5 V
2V > VIN + 0.5 V

I get a VIN of 1.5 Volts. The correct answer is -0.5 V. I'm just starting to learn electrical engineering and it would be great if someone can point out what's missing.
 

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I figured it out.
VGS > VT
hence
VIN - VS- > 0.5 V
VIN + 1 > 0.5 V
VIN = -0.5
VIN can vary from -0.5 to 1.5;
 
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