Motion at Constant Acceleration Question 3

AI Thread Summary
A car decelerates uniformly from 21.0 m/s to rest over 6.00 seconds, prompting a calculation of the distance traveled during this time. The average speed during this deceleration is determined to be 10.5 m/s, not 3.5 m/s, as it is the mean of the initial and final speeds. The distance traveled can be calculated using the formula: distance = average speed × time, resulting in a total distance of 63 meters. Understanding that the average speed is derived from the initial and final speeds, rather than dividing the initial speed by time, clarifies the confusion. The key takeaway is that with constant deceleration, the average speed is crucial for calculating distance.
Adrianna
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Homework Statement


A car slows down uniformly from a speed of 21.0 m/s to rest in 6.00s. How far did it travel in that time?


Homework Equations



I am not really sure what one to use, which is the problem.

The Attempt at a Solution

 
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First, if it slows from 21 to 0 uniformly, what's the average speed at which the car travels within those 6 seconds? Then, what is the distance the car travels in 6 seconds at that average speed?
 
the average speed is 3.5 m/s it travels 21 m in 6 seconds right?
 
Is the average speed 3.5m/s?

Why would 21m/s divided by 6 give you the average speed?
 
Im not really sure I'm really confused... I thought that 21 was the distance and 6 was the time but I know that is wrong so isn't 21 m/s the average speed?
 
If the initial speed is 21 and the final speed is 0, and the deceleration is uniform, what do you think the average speed is? Just from intuition, the answer should be obvious, though the proof requires calculus.

For finding the average speed, disregard the fact that it took 6 seconds. How long it took to decelerate is unimportant. What is important is that the deceleration was constant.
 
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