Motion - Overtaking Vehicles question

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A car is attempting to overtake a truck traveling at 60 km/h while the car accelerates to 90 km/h. The car needs to be 15 meters in front of the truck after overtaking, and the total distance to cover during the maneuver is 45 meters (15m truck length plus 15m car length plus 15m safety distance). The calculated time to complete the overtaking is 5.4 seconds. During this time, the car travels 135 meters, while the oncoming vehicle, traveling at 90 km/h, covers 150 meters, which indicates that the overtaking is unsafe as the two vehicles would meet before the maneuver is completed. Therefore, the car should not overtake.
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Homework Statement



A car is traveling 15m behind a 15m long truck. The speed limit is 90km/hr. But the truck is traveling at 60 km/hr. the car wants to overtake the truck, and when it does, it reaches speed of 90km/hr and has to be 15m in front of the truck in order to do this. The car will be parallel with the truck (I think it means beside it in a 2 lane road). However an oncoming vehicle traveling at 90km/hr is 400m away from the vehicle. Should the vehicle overtaking overtake or not?

Homework Equations



L / (Vb - Va)

Where L is the distance, and Vb is the velocity of the vehicle trying to overtake, and Va is the velocity of the car that is being overtaken (in this instance the truck).

The Attempt at a Solution



I began with:

60 km/h = 16.67 m/s
90 km/h = 25 m/s

Therefore:
Time to overtake = L / (Vb - Va)
= (15 + 15 + 15) / (25 - 16.67)
= 5.4 seconds

That's all I could do. Sorry this topic is new to me and my exam is tomorrow. The teacher handed us practice questions without solutions on our last lesson. All help would greatly be appreciated.
 
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What is the distance the car travels in those 5.4 seconds? What is the distance the other car travels in that time?
 

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