Moving electron under two magnetic fields

AI Thread Summary
The discussion focuses on calculating the force on an electron under two magnetic fields, emphasizing the importance of considering the electron's mass. Participants clarify that the exercise requires determining the force at a specific time rather than calculating a trajectory. They agree that the problem lacks information about a point in time, making it unnecessary to include distance in the calculations. The correct approach involves using known values for position, velocity, and magnetic fields at time t. Overall, the conversation highlights the need for a straightforward application of the Lorentz force equation without extraneous variables.
merdeka
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Homework Statement
A coil ##\vec{B}## a current of intensity ##i## created in ##M## a magnetic field ##\vec{B}_1##. A magnet ##A## created in ##M## a magnetic field ##\vec{B}_2## .

What is the force undergone by a charge particle ##q## with a velocity ##\vec{v}## that is in ##M## at time ##t## ?

Taking into account the mass of the electron.
Relevant Equations
##F=q\cdot v\cdot B\cdot\sin(\vec{v},\vec{B})##
Moving_particle_2_mag_fields_with_vectors_on_M.svg.png


In this question, I would have to calculate the force in respect to time. However, the question gives me the value of the mass of the electron. In my attempt, I didn't take that into account. I just replaced ##v## with ##\frac{d}{t}## and made the Lorentz force undergone by the particle inversely proportional, but this is probably not correct.
 
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Hi,

merdeka said:
the force in respect to time
I think the exercise asks for the force at time ##t## and doesn't want you to calculate a trajectory. (For which there is no information given anyway)
 
BvU said:
Hi,

I think the exercise asks for the force at time ##t## and doesn't want you to calculate a trajectory. (For which there is no information given anyway)
The question didn't give any information or value for a point in time.
 
So we agree on that. At time ##t##, position, velocity and field are known. There is no ##d## in the problem and you don't need it. Calculate in a straightforward manner with the equation you mention..
 
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