Multiple independent exponential random variables

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SUMMARY

The discussion focuses on determining the distribution of the minimum of multiple independent exponential random variables, specifically denoted as min(X1, X2, ..., Xn), where each variable shares a common parameter gamma. The key insight provided is that the probability min(X1, X2, ..., Xn) > x is equivalent to the product of the individual probabilities, expressed as P(X1 > x) * P(X2 > x) * ... * P(Xn > x). This leads to the conclusion that the minimum of these variables follows an exponential distribution with parameter n * gamma.

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libragirl79
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Let X1, X2, ...Xn be independent exponential variables having a common parameter gamma. Determine the distribution of min(X1,X2, ...Xn).




The Attempt at a Solution


I know how to do it with one X and one parameter but I am at a loss with these multiple ones...

Thanks so much!
 
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Hint: min(X1,X2,...Xn)>x is equivalent to saying X1>x and X2>x and... Xn>x.

You can find the latter probability by multiplying the probabilities of each event.
 

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