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Multivariable extrema

  1. Oct 28, 2012 #1
    1. The problem statement, all variables and given/known data
    f(x,y) = x^3 - 3x^2 - 6xy + 7y + y^2, x>=0, y>=0
    i) Explain why f attains its minimum value on the quadrant.
    ii) Find the critical points and classify them


    2. Relevant equations
    df/dx = 3x^2 - 6x -6y
    df/dy = -6x + 7 +2y

    d^2f/dx^2 = 6x-6
    d^2f/dy^2 = 2
    d^2f/(dxdy) = -6

    3. The attempt at a solution
    It's been awhile since I've done problems like this. Hopefully I am making some sense.
    I'm not sure about i). Couldn't x=-infinity and y=-1 yield -infinity?
    For ii) I get the critical points to be (7, 35/2) and (1, -1/2), but (1, -1/2) is not in the constraints. fxx is positive and the determinant of the Hessian at the first point is negative so it is a saddle point. If the constraints weren't there, how would I figure out the other point since fxx=0?
    iii) I'm not sure the best way to go about this. Help would be appreciated.
    Thanks
     
  2. jcsd
  3. Oct 28, 2012 #2

    Ray Vickson

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    Homework Helper

    If f(x,y) does attain a minimum in {x,y ≥ 0} it does so either at an interior point (i.e., a stationary point) or on the boundary ({x=0} or {y=0}). You can check f along the two boundary lines {x=0,y≥0} and {y=0,x≥0}. Then, the only remaining question is whether f is bounded from below in the first quadrant. If I were doing the question I would check whether f is bounded from below on the non-negative x and y axes, and if it is bounded from below for points of the form (x,k*x) with k > 0 and x ≥ 0.

    RGV
     
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