Natural log (ln x) derivative question

SteveM19
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Homework Statement



This is to help out a 40something calc student -- thank you all in advance for your help


Homework Equations



If f (y) = ln ln ln x, what is ∂y/∂x?

The Attempt at a Solution



I came up with 1/x, which I got by applying ∂y/∂x ln x = 1/x three times, is this right? Thank you again for your help.
 
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Is that a ##f(y)##? Or like ##f(x) = y =~ ...##
 
BloodyFrozen said:
Is that a ##f(y)##? Or like ##f(x) = y =~ ...##

I might have used the terminology incorrectly --

y = ln ln ln x

What is y prime?
 
SteveM19 said:

Homework Statement



This is to help out a 40something calc student -- thank you all in advance for your help

Homework Equations



If f (y) = ln ln ln x, what is ∂y/∂x?
As BloodyFrozen already noted, that should be f(x) = ...

Also, the problem should be asking for dy/dx, not ∂y/∂x, which is the partial derivative of y with respect to x. Unless I'm missing something, you want the ordinary derivative, dy/dx.
SteveM19 said:

The Attempt at a Solution



I came up with 1/x, which I got by applying ∂y/∂x ln x = 1/x three times, is this right? Thank you again for your help.
No, it's not right. You have a composite function, y = ln(ln(ln(x))), so you need to use the chain rule a couple of times. It also might be helpful to include parentheses as I did.In response to your other question, you can take y' to be a synonym of dy/dx.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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